To increase the force between two charges from 25 N to 100 N, one should​

Correct option is B

The correct answer is (B) reduce the distance between the charges by half

Explanation:

force between two charges is governed by Coulomb's Law, which states that the electrostatic force (F) between two charges is inversely proportional to the square of the distance (r) between them. The law is given by:

​$$F= k \frac{q_1 q_2}{r^2}$$​​

Where:

• F is the electrostatic force,

• q₁ and q₂are the magnitudes of the charges,

• rr is the distance between the charges,

• kk is Coulomb's constant.

To increase the force from 25 N to 100 N, we need to decrease the distance between the charges, since force is inversely proportional to the square of the distance. Specifically, reducing the distance by half increases the force four times (since force is proportional to 1r2\frac{1}{r^2}), and this matches the required increase in force from 25 N to 100 N.

Information Booster:

• According to Coulomb's Law, halving the distance between two charges increases the force by a factor of 2²= 4.

• If the force between the charges initially is 25 N, halving the distance will result in a force of 100 N, which is four times the original force.

• The inverse square law of Coulomb's Law is crucial in understanding how the force changes with distance.

• Coulomb's Law applies to point charges, and the relationship holds true in a vacuum or air.