Three numbers are in the ratio $$\frac{4}{14}:\frac{7}{14}:\frac{16}{15}.$$​ The difference between the largest and the smallest number is 41.
Find the largest number.​

Correct option is C

Given: ​

Ratio = $$\frac{4}{14}:\frac{7}{14}:\frac{16}{15}$$  

Largest number - smallest number = 41 

Solution: ​

​$$\frac{4}{14}:\frac{7}{14}:\frac{16}{15} \\ \ \\ = 60 : 105 : 224$$ 

Now; 

(224 - 60) unit = 41 

164 unit = 41 

1 unit = $$\frac{41}{164} = \frac{1}{4}$$​​

Now, for largest number 

224 unit = $$\frac{1}{4}\times 224 = 56$$​​