Three numbers A, B and C are in the ratio of 5: 4:3 respectively. If C is 18 less than the sum of A and B, then what is the value of B?

Correct option is D

Given:

The ratio of A:B:C = 5:4:3
C is 18 less than the sum of A and B
Solution:
Now numbers will be 5x, 4x, 3x
C = (A+B) − 18
3x = (5x+4x)-18
9x-3x = 18
6x = 18
x = 3
Value of B = 4x =4×3=12​​