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    Three coins are tossed simultaneously. Find the probability of getting exactly two heads.
    Question

    Three coins are tossed simultaneously. Find the probability of getting exactly two heads.

    A.

    58\frac{5}{8}

    B.

    18\frac{1}{8}

    C.

    12\frac{1}{2}​​

    D.

    38\frac{3}{8}​​

    Correct option is D

    Solution:

    Step 1: Total possible outcomes
    When three coins are tossed, the total number of outcomes is given by:
    23=82^3 = 8
    The possible outcomes are:
    HHH, HHT, HTH, HTT, THH, THT, TTH, TTT

    Step 2: Favorable outcomes
    We need exactly two heads. The outcomes with exactly two heads are:
    HHT, HTH, THH
    There are 3 favorable outcomes.

    Step 3: Probability formula
    The probability is given by:
    P(exactly two heads)=Number of favorable outcomesTotal number of outcomesP(\text{exactly two heads}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}
    Substitute the values:
    P(exactly two heads)=38P(\text{exactly two heads}) = \frac{3}{8}

    Final Answer:

    The probability of getting exactly two heads is:
    38\frac{3}{8}

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