Three coins are tossed simultaneously. Find the probability of getting exactly two heads.

Correct option is D

Solution:

Step 1: Total possible outcomes
When three coins are tossed, the total number of outcomes is given by:
$$2^3 = 8$$​
The possible outcomes are:
HHH, HHT, HTH, HTT, THH, THT, TTH, TTT

Step 2: Favorable outcomes
We need exactly two heads. The outcomes with exactly two heads are:
HHT, HTH, THH
There are 3 favorable outcomes.

Step 3: Probability formula
The probability is given by:
$$P(\text{exactly two heads}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$$​
Substitute the values:
$$P(\text{exactly two heads}) = \frac{3}{8}$$​

Final Answer:

The probability of getting exactly two heads is:
$$\frac{3}{8}$$​