From a group of 37 men and 13 women, 3 persons are selected at random. Find the probability that out of the selected three persons, two are women and one is man.
(Approximately in %)

Correct option is D

Total persons = 37 men + 13 women
= 50

Total ways to select 3 persons
= C(50,3)
= 19600

Ways to select 2 women and 1 man
= C(13,2) × C(37,1)

= 78 × 37
= 2886

Probability
= 2886 / 19600
≈ 0.1472

In percentage
≈ 14.72%