Correct option is D
Total persons = 37 men + 13 women
= 50
Total ways to select 3 persons
= C(50,3)
= 19600
Ways to select 2 women and 1 man
= C(13,2) × C(37,1)
= 78 × 37
= 2886
Probability
= 2886 / 19600
≈ 0.1472
In percentage
≈ 14.72%
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Question
From a group of 37 men and 13 women, 3 persons are selected at random. Find the probability that out of the selected three persons, two are women and one is man.
(Approximately in %)
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