Correct option is D
Given:
6-storey building with 20 rooms on each floor
Three groups of officers start the search operation simultaneously
The first group searches the 1st and 2nd floors
The second group handles the 3rd and 4th floors
The third group takes over the 5th and 6th floors
It takes 1 minute to reach any nearest floor
It takes 1 minute to search each room
Formula Used:
Total time for each group = time to search rooms on both floors + time to move between floors + time to reach the first floor they search
Calculation:
Total rooms on each floor = 20
Time to search one floor = 20 minutes
Total rooms for each group (2 floors) = 20 + 20 = 40
Time to search rooms on both floors for each group = 40 minutes
Time to move between the two floors = 1 minute
Time to reach the first floor:
The first group does not need additional time as they start from the 1st floor.
The second group needs 2 minutes to reach the 3rd floor from the 1st floor.
The third group needs 4 minutes to reach the 5th floor from the 1st floor.
First group:
Time to search rooms on both floors + time to move between floors
Total time = 40 + 1 = 41 minutes
Second group:
Time to reach the 3rd floor + time to search rooms on both floors + time to move between floors
Total time = 2 + 40 + 1 = 43 minutes
Third group:
Time to reach the 5th floor + time to search rooms on both floors + time to move between floors
Total time = 4 + 40 + 1 = 45 minutes
Since all groups start simultaneously, the total time taken to complete the entire search operation will be the maximum time taken by any group.
Therefore, the total time to complete the entire search operation is 46 minutes.
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100 Questions
100 Marks
90 Mins
