The value of the expression

​$$(1+\frac{1}{3})(1+\frac{1}{4})(1+\frac{1}{5})...(1+\frac{1}{n-1})$$ is:​

Correct option is A

Given:

The expression is

​$$\left(1 + \frac{1}{3}\right)\left(1 + \frac{1}{4}\right)\left(1 + \frac{1}{5}\right)\cdots \left(1 + \frac{1}{n-1}\right)$$​​

Solution:​

​$$\left(1 + \frac{1}{3}\right)\left(1 + \frac{1}{4}\right)\left(1 + \frac{1}{5}\right)\cdots \left(1 + \frac{1}{n-1}\right)$$​​

= $$\frac{4}{3} \times \frac{5}{4} \times \frac{6}{5} \times \cdots \times \frac{n}{n-1}$$​​

​$$=\frac{n}{3}$$​

Thus, the value of the expression is $$\frac{n}{3}.$$​​