Correct option is AGiven: We are to evaluate the expression:1−11+12−12+131 - \frac{1}{1 + \frac{1}{2 - \frac{1}{2 + \frac{1}{3}}}}1−1+2−2+31111Solution:1−11+12−12+131 - \frac{1}{1 + \frac{1}{2 - \frac{1}{2 + \frac{1}{3}}}}1−1+2−2+31111=1−11+12−1731 - \frac{1}{1 + \frac{1}{2 - \frac{1}{\frac{7}{3}}}}1−1+2−37111=1−11+12−371 - \frac{1}{1 + \frac{1}{2 - \frac{3}7}}1−1+2−7311=1−11+11171 - \frac{1}{1 + \frac{1}{ \frac{11}7}}1−1+71111=1−11+7111 - \frac{1}{1 + \frac{7}{11}}1−1+1171=1−118111 - \frac{1}{ \frac{18}{11}}1−11181=1−11181-\frac{11}{18}1−1811 =18−1118=718\frac {18-11}{18}=\frac {7}{18}1818−11=187