The value of $$\frac{0.064+0.027}{0.16-0.12+0.09}$$​ is:​​

Correct option is C

Given: ​

​$$\frac{0.064+0.027}{0.16-0.12+0.09}$$ 

Formula Used: ​

​$$a^3 + b^3 = (a + b)(a^2 - ab + b^2)$$ 

Solution: ​

​$$\frac{0.064+0.027}{0.16-0.12+0.09} \\ \ \\ = \frac{(0.4)^3+(0.3)^3}{(0.4)^2-0.3 \times 0.4+(0.3)^2}\\ \ \\ = \frac{(0.4+0.3)[(0.4)^2-0.3 \times 0.4+(0.3)^2]}{(0.4)^2-0.3 \times 0.4+(0.3)^2} \\ \ \\ = 0.4+0.3 \\ \ \\ = 0.7$$​​