arrow
arrow
arrow
The total inductance of two coupled coils in the series opposing and series aiding connections are 12 mH and 38 mH, respectively. Find the mutual indu
Question

The total inductance of two coupled coils in the series opposing and series aiding connections are 12 mH and 38 mH, respectively. Find the mutual inductance between the coils.

A.

13 mH

B.

26 mH

C.

10 mH

D.

6.5 mH

Correct option is D

Given: Laiding=38 mH Lopposing=12 mHFor two magnetically coupled coils:Laiding=L1+L2+2MLopposing=L1+L22MSubtracting the two equations:LaidingLopposing=4M3812=4M=>26=4M=>M=264=6.5 mH\text{Given:} \\[4pt]\bullet \; L_{\text{aiding}} = 38\,\text{mH} \\[4pt]\bullet \; L_{\text{opposing}} = 12\,\text{mH} \\[8pt]\text{For two magnetically coupled coils:} \\[4pt]L_{\text{aiding}} = L_1 + L_2 + 2M \\[4pt]L_{\text{opposing}} = L_1 + L_2 - 2M \\[8pt]\text{Subtracting the two equations:} \\[4pt]L_{\text{aiding}} - L_{\text{opposing}} = 4M \\[8pt]38 - 12 = 4M \Rightarrow 26 = 4M \Rightarrow M = \frac{26}{4} = 6.5\,\text{mH}​​

test-prime-package

Access ‘SSC JE Electrical’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
340k+ students have already unlocked exclusive benefits with Test Prime!
test-prime-package

Access ‘SSC JE Electrical’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
340k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow