The table here gives the yield of wheat per hectare of 100 farmers of a village. What is the cumulative frequency of the class preceding the median class?
Production yield (Qui/Hec) | Number of farmers |
30-40 | 5 |
40-50 | 18 |
50-60 | 15 |
60-70 | 22 |
70-80 | 27 |
80-90 | 13 |
Solution:
total number of farmers (N):
N = 5 + 18 + 15 + 22 + 27 + 13 = 100
= = 50 falls in the class 60-70
The median class is 60-70.
The class preceding 60-70 is50-60.
From the table,
the cumulative frequency of 50-60 = 38.
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90 Mins English English100 Questions100 Marks90 Mins English English40 Questions30 Marks25 Mins EnglishIf x and y are upper limit of median class and lower limit of modal class, respectively in the following distribution, then what is the value of (2x + y)?
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