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    ​The sum of two numbers is 15. If the sum of their reciprocals is 310\frac{3}{10}103​​ then find the two numbers?​
    Question

    The sum of two numbers is 15. If the sum of their reciprocals is 310\frac{3}{10}​ then find the two numbers?

    A.

    7, 8

    B.

    5, 10

    C.

    6, 9

    D.

    -5, 20

    Correct option is B

    Given:

    Sum of two numbers = 15

    Sum of their reciprocals = 310\frac{3}{10}

    Solution:

    The first number is 'x'

    The second number is 'y'

    Sum of the numbers: x + y = 15 ......(1)

    Sum of their reciprocals: 1x+1y\frac{1}{x} + \frac{1}{y}​ = 310\frac{3}{10}  .....(2)​

    From equation 1, we can express y in terms of x:

    y = 15 - x

    Substitute the value of y in equation 2:

    1x+115x\frac{1}{x} + \frac{1}{15-x}​​= 310\frac{3}{10}

    (15x+x)x(15x)\frac{(15 - x + x)} { x(15 - x)}​= 310\frac{3}{10}​  .

    150 = 45x - 3x2

    3x2 - 45x + 150 = 0

    x2 - 15x + 50 = 0

    (x - 10)(x - 5) = 0

    x = 10 or x = 5

    Find the corresponding values of y:

    If x = 10, then y = 15 - 10 = 5

    If x = 5, then y = 15 - 5 = 10

    Therefore, the two numbers are 5 and 10.

    Option (b) is right answer.

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