The sum of three consecutive natural numbers is 120. Find the largest number.
Given:
The sum of these numbers is given as 120.
Solution:
Let the number be x , x+1 , x+2
Now,
x + x + 1 + x + 2 = 120
3x + 3 = 120
3x = 117
x = 39
The three consecutive numbers are 39, 40, and 41.
The largest number is 41
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