The sum of the square of the first ten natural numbers is:

Correct option is C

Given:
First ten natural numbers: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
Formula Used:
Sum of squares of first n natural numbers = $$\frac{n(n + 1)(2n + 1) }{6}$$​​
Solution:
​$$\text {Sum }= \frac {10(10 + 1)(2×10 + 1)}{ 6} = \frac{10 × 11 × 21}{ 6}\\\text {Sum } = \frac { 2310}{6} = 385\\$$​​
Alternate Solution:
You can directly calculate the sum by adding the squares of individual numbers:
1² + 2² + 3² + 4² + 5² + 6² + 7² + 8² + 9² + 10² = 385