Given:
We are to find the smallest number which when decreased by 3 is divisible by 15, 25, and 55.
Solution:
Prime factorizations:
15 = 3 × 5
25 = 52
55 = 5 × 11
LCM(15, 25, 55) = 3 × 52 × 111 = 3 × 25 × 11 = 825
Thus, the smallest number is 825 + 3 = 828
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