The smallest natural number which is divisible by 12, 28, 36 and 27 is:

Correct option is C

Given:

We are to find the smallest natural number divisible by:

12, 28, 36, and 27.

Solution:

Prime factorization:

12 = $$2^2 \times 3$$​​

28 = $$2^2 \times 7$$​​

36 = $$2^2 \times 3^2$$​​

27 = $$3^3$$​​

LCM = $$2^2 \times 3^3 \times 7 = 4 \times 27 \times 7$$​ = 756