The smallest 6 digit number which is completely divisible by 21 is

Correct option is D

Given:

Smallest 6-digit number divisible by 21

Formula Used:

Smallest multiple of a number ≥ (N)

Required number = $$\lceil \frac{N}{d} \rceil \times d$$​​

Solution:

Smallest 6-digit number = 100000

 Divide by 21:

$$\frac{100000}{21} \approx$$​4761.9

Next integer = 4762

Required number = 4762 × 21 = 100002

Smallest 6-digit number divisible by 21 = 100002