Correct option is BGiven:0.752−0.2522×2.52−1.524×10.25\frac{0.75^2 - 0.25^2}{2} \times \frac{2.5^2 - 1.5^2}{4} \times \frac{1}{0.25} 20.752−0.252×42.52−1.52×0.251Solution:(0.75−0.25)(0.75+0.25)2×(2.5−1.5)(2.5+1.5)4×10.25\frac{(0.75 - 0.25)(0.75 + 0.25)}{2} \times \frac{(2.5 - 1.5)(2.5+1.5)}{4} \times \frac{1}{0.25} 2(0.75−0.25)(0.75+0.25)×4(2.5−1.5)(2.5+1.5)×0.251= 0.50×12×1×44×10.25\frac{0.50 \times1}{2} \times \frac{1\times4}{4} \times \frac{1}{0.25} 20.50×1×41×4×0.251= 1