The simple interest earned on ₹2,800 at a rate of 10% per annum for 3 years is ₹x and ₹1,736 is the simple interest earned on ₹ 6,200 at a rate of 14% for y years, then the value of x/y is:

Correct option is C

Given:
For, First Condition
Principal, P1 = ₹2800,
Rate of interest, r1 = 10%,
Time, t1 = 3 years
Simple Interest, S.I = ₹ x
For, Second Condition;
Principal, P2 = ₹6,200,
Rate of interest, r2 = 14%,
Time, t2 = y years
Simple Interest, S.I = ₹ 1,736
Formula Used:
​$$\text{Simple Interest} = \frac{P \times r \times t}{100}$$​​
Where, P = Principal, r = rate of interest, t = time
Solution:
As per the question;
For, first condition;
S.I = (2800×10×3)/100=840
So, x = ₹ 840
Again, For, second condition;
1736 = (6200×14×y)/100
y = (1736×100)/(6200×14)
y = 2 years
therefore,
required sol. = x/y
= 840/2 = 420