What is the rate percent and time needed, both of them being equal in value, for the simple interest on a certain sum to be 36 over 100 of that sum?

Correct option is C

Given:
Simple Interest (SI) = 36/100 of Principal (P)
Rate (R) = Time (T)
Formula Used:
SI = $$\frac{P × R × T}{100}$$​​
Solution:
Substitute the given values into the formula:
​$$\frac{36}{100} × P = \frac{P × R × R}{100}$$​​
​$$36 = R^2$$​​
Take the square root of both sides:
R = 6
Since Rate and Time are numerically equal:
Rate = 6% and Time = 6 years.
Final Answer
So the correct answer is (c)