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The roots of the equation 3x2+5x−a=03x^2+ 5x-a = 03x2+5x−a=0​ are the reciprocals of each other. What is the value of a?
Question

The roots of the equation 3x2+5xa=03x^2+ 5x-a = 0​ are the reciprocals of each other. What is the value of a?

A.

3

B.

–3

C.

–2

D.

2

Correct option is B

Given:

3x2+5xa=03x^2 + 5x - a = 0 

Roots of the equation are reciprocals 

Concept Used:

If the roots of the quadratic equationAx2+Bx+C=0Ax^2 + Bx + C = 0​ are r1r_1 and r2r_2​ . Then 

the sum of the roots is given by: r1+r2=BAr_1+r_2= - \frac{B}{A} 

And The product of the roots is given by: r1r2=CAr_1 \cdot r_2 = \frac{C}{A} 

Solution:

We are given the quadratic equation: 

3x2+5xa=03x^2 + 5x - a = 0 

​Let the roots of the quadratic equation be r1r_1​and r2r_2 According to the problem, these roots are reciprocals, so:

r1=1r2r_1= \frac{1}{r_2} 

​For the equation 3x2+5xa=03x^2 + 5x - a = 0 , 

The sum of the roots is: 

r1+r2=BAr_1+r_2= - \frac{B}{A}  =  53\frac{5}{3} 

The product of the roots is:

r1×r2=CA=a3r_1 \times r_2 = \frac{C}{A} = \frac{-a}{3} 

Since the roots are reciprocals, we have r1=1r2r_1= \frac{1}{r_2}​, so the product of the roots is:

r1×r2=1r_1 \times r_2 = 1 

a3=1\frac{-a}{3}= 1 

−a =3  =>  a  = −3 

Thus the value of aaa is -3 .−3\boxed{-3}


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