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    The resistance of a wire of length l , radius r , and resistivity ρ\rho ρ is,
    Question

    The resistance of a wire of length l , radius r , and resistivity ρ\rho  is,

    A.

    R=ρl4πrR = \frac{\rho l}{4 \pi r}​​

    B.

    R=ρl2πrR = \frac{\rho l}{2 \pi r}​​

    C.

    R=ρl4πr2R = \frac{\rho l}{4 \pi r^2}​​

    D.

    R=ρlπr2R = \frac{\rho l}{ \pi r^2}​​

    Correct option is D

    Solution ​​

    The formula for the resistance RRR of a wire is derived from the equation:
    R=ρlAR = \rho \frac{l}{A}​​

    Where:

    • ρ\rhoρ: Resistivity of the material of the wire.
    • lll: Length of the wire.
    • AAA: Cross-sectional area of the wire.
    • A=πr2A = \pi r^2

    The cross-sectional area of the wire, AAA, is given by:

    Substituting AAA into the resistance formula:
    R=ρlπr2R = ρ\frac{ l}{\pi r^2}

    Thus, the correct option is D.

    Information Booster

    Resistance and Its Dependence

    • Length (l): Resistance is directly proportional to the length of the wire. Longer wires have higher resistance.
    • Cross-sectional Area (A): Resistance is inversely proportional to the area. Larger areas result in lower resistance.
    • Resistivity (ρ): Resistance depends on the material and its resistivity, which is a constant for a specific material.

    Role of Radius

    • Since A=πr2A = \pi r^2A=πr2A = \pi r^2​, the radius of the wire significantly affects the resistance. Smaller radii result in larger resistance values.

    Applications of Resistance Formula

    • Design of Electrical Circuits: Used in selecting wire dimensions to control current flow.
    • Material Science: Helps in understanding the electrical properties of different materials.

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