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The resistance of a wire of length l , radius r , and resistivity ρ\rho ρ is,
Question

The resistance of a wire of length l , radius r , and resistivity ρ\rho  is,

A.

R=ρl4πrR = \frac{\rho l}{4 \pi r}​​

B.

R=ρl2πrR = \frac{\rho l}{2 \pi r}​​

C.

R=ρl4πr2R = \frac{\rho l}{4 \pi r^2}​​

D.

R=ρlπr2R = \frac{\rho l}{ \pi r^2}​​

Correct option is D

Solution ​​

The formula for the resistance RRR of a wire is derived from the equation:
R=ρlAR = \rho \frac{l}{A}​​

Where:

  • ρ\rhoρ: Resistivity of the material of the wire.
  • lll: Length of the wire.
  • AAA: Cross-sectional area of the wire.
  • A=πr2A = \pi r^2

The cross-sectional area of the wire, AAA, is given by:

Substituting AAA into the resistance formula:
R=ρlπr2R = ρ\frac{ l}{\pi r^2}

Thus, the correct option is D.

Information Booster

Resistance and Its Dependence

  • Length (l): Resistance is directly proportional to the length of the wire. Longer wires have higher resistance.
  • Cross-sectional Area (A): Resistance is inversely proportional to the area. Larger areas result in lower resistance.
  • Resistivity (ρ): Resistance depends on the material and its resistivity, which is a constant for a specific material.

Role of Radius

  • Since A=πr2A = \pi r^2A=πr2A = \pi r^2​, the radius of the wire significantly affects the resistance. Smaller radii result in larger resistance values.

Applications of Resistance Formula

  • Design of Electrical Circuits: Used in selecting wire dimensions to control current flow.
  • Material Science: Helps in understanding the electrical properties of different materials.

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