The remainder, when $$11^{41}+3$$​ is divided by 10, is:

Correct option is D

Given:

We are asked to find the remainder when $$11^{41} + 3$$​ is divided by 10.

Solution:

​$$11^1$$​ = 11 → last digit is 1.

​$$11^2 = 121$$​ → last digit is 1.

​$$11^3 = 1331$$​→ last digit is 1.

​$$11^4 = 1464$$​1 → last digit is 1.

We observe that the last digit of all powers of 11 is 1.

So, $$11^{41}$$​ will also end in 1, meaning the last digit of $$11^{41}$$​ is 1.

Now, add 3 to this:

1 + 3 = 4

Thus, the remainder when $$11^{41} + 3$$​ is divided by 10 is 4.