The Q-factor of an RLC circuit is 5 at its resonance frequency of 2 kHz. Find the bandwidth of the circuit.

Correct option is B

​$$\text{To find the bandwidth of an RLC circuit, we can use the relationship between the quality factor (Q factor), resonance frequency ($f_0$), and bandwidth (BW). The formula is:}\\Q = \frac{f_0}{\text{BW}}\\\text{Given:}\\\begin{aligned}Q &= 5 \\f_0 &= 2\text{ kHz} = 2000 \text{ Hz}\\\end{aligned}\\\text{Rearranging the formula to solve for bandwidth:}\\\begin{aligned}\text{BW} &= \frac{f_0}{Q}\end{aligned}\\\text{Substituting the given values:}\\\begin{aligned}\\\text{BW} &= \frac{2000 \text{ Hz}}{5} = 400 \text{ Hz}\end{aligned}\\\text{Therefore, the bandwidth of the circuit is } (b) \ 400 \text{ Hz}.$$​​