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    The price of fuel decreases by 35%, 10% and 30% in three successive months, but increases by 65% in the fourth month. What is the percentage increase/
    Question

    The price of fuel decreases by 35%, 10% and 30% in three successive months, but increases by 65% in the fourth month. What is the percentage increase/decrease in the price of fuel in the fourth month as compared to its original price?

    A.

    Decreases by 33.75%

    B.

    Decreases by 32.43%

    C.

    Increases by 31.14%

    D.

    Increases by 32.84%

    Correct option is B

    Given:
    Decreases by 35%
    Decreases by 10%
    Decreases by 30%
    Increases by 65%

    Concept Used:

    Successive percentage decrease or increase;

    New Price=Original Price×(1+Change1100)×(1+Change2100)×(1+Change3100)×(1+Change4100)\text{New Price} = \text{Original Price} \times \left( 1 + \frac{\text{Change}_1}{100} \right) \times \left( 1 + \frac{\text{Change}_2}{100} \right) \times \left( 1 + \frac{\text{Change}_3}{100} \right) \times \left( 1 + \frac{\text{Change}_4}{100} \right)

    Solution:

    Applying the formula;

    100×(135100)×(110100)×(130100)×(1+65100)100 \times \left(1 - \frac{35}{100} \right) \times \left(1 - \frac{10}{100} \right)\times \left(1 - \frac{30}{100} \right) \times \left(1 + \frac{65}{100} \right)

    100×(65100)×(90100)×(70100)×(165100)100\times \left( \frac{65}{100} \right)\times \left( \frac{90}{100} \right) \times \left( \frac{70}{100} \right) \times \left( \frac{165}{100} \right) 

    = 67.57%

    So, the change in price decreases by = 100 - 67.57% = 32.43% 

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