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    The plot below has two curves (A, B) that show the fractional occupancy of hemoglobin and myoglobin by oxygen as a function of the amount of oxygen.Th
    Question

    The plot below has two curves (A, B) that show the fractional occupancy of hemoglobin and myoglobin by oxygen as a function of the amount of oxygen.

    The two reactions are

    i. E+SES\mathrm{E} + \mathrm{S} \rightleftharpoons \mathrm{ES} and​

    ii. E+nSESn\mathrm{E} + n\mathrm{S} \rightleftharpoons \mathrm{ES}_n​​

    where S is O2O_2  and E is myoglobin or hemoglobin

    The equations that could be used to fit the two curves are:

    I. Yα=[O2]nK+[O2]nY_{\alpha} = \frac{[\mathrm{O}_2]^n}{K + [\mathrm{O}_2]^n}​​

    II. Yα=(pO2)nK+(pO2)nwhere K=[E][S]n[ESn]Y_{\alpha} = \frac{(p\mathrm{O}_2)^n}{K + (p\mathrm{O}_2)^n}\qquad \text{where } K = \frac{[\mathrm{E}][\mathrm{S}]^n}{[\mathrm{ES}_n]}​​

    III. Yα=[O2]K+[O2]Y_{\alpha} = \frac{[\mathrm{O}_2]}{K + [\mathrm{O}_2]}​​

    IV. Yα=(pO2)K+(pO2)where K=[E][S][ES]Y_{\alpha} = \frac{(p\mathrm{O}_2)}{K + (p\mathrm{O}_2)}\qquad \text{where } K = \frac{[\mathrm{E}][\mathrm{S}]}{[\mathrm{ES}]}

    YO2Y_{O2} is the fraction of oxygen-binding sites occupied by oxygen. pO2pO_2 is partial pressure of oxygen.

    From the options given below, select the option with the right curve (A,B), reaction (i, ii) and equation/s (I, II, III, IV) that describe oxygen binding to hemoglobin and myoglobin.

    A.

    Myoglobin: curve A, reaction i, equations III and IV. Hemoglobin: curve B, reaction ii, equations I and II.

    B.

    Myoglobin: curve B, reaction i, equations II and IV. Hemoglobin: curve A, reaction ii, equations I and III.

    C.

    Myoglobin: curve A, reaction ii, equations III and IV. Hemoglobin: curve B, reaction i, equations I and II.

    D.

    Myoglobin: curve A, reaction ii, equations I and II. Hemoglobin: curve B, reaction i, equations III and IV.

    Correct option is A

    (a) Myoglobin: curve A, reaction i, equations III and IV. Hemoglobin: curve B, reaction ii, equations I and II.

    Sol. Let's break down the given information:

    • Curve A is characteristic of myoglobin. The graph shows a hyperbolic curve that is typical for myoglobin because it binds oxygen in a non-cooperative manner. As the oxygen concentration increases, myoglobin binds oxygen in a steady, almost linear fashion, indicating a hyperbolic binding curve.

    • Curve B represents hemoglobin, which shows a sigmoidal (S-shaped) curve, indicating cooperative binding. As the first molecule of oxygen binds to hemoglobin, the molecule undergoes a conformational change that makes it easier for subsequent oxygen molecules to bind. This cooperativity is reflected in the sigmoidal curve.

      Myoglobin binds oxygen using the reaction i (E + S ↔ ES) and its equation is described by equation III, where the fraction of binding sites occupied by oxygen (Y_o) is given by the relationship Yo=[O2]nK+[O2]nY_o = \frac{[O_2]^n}{K + [O_2]^n} where K is the dissociation constant and n is the Hill coefficient, which reflects the degree of cooperativity. Since myoglobin binds oxygen non-cooperatively, n = 1.

      Hemoglobin binds oxygen cooperatively, described by reaction ii (E + nS ↔ ES_n), and the equation used to describe this cooperativity is equation I: Yo=(pO2)nK+(pO2)nY_o = \frac{(pO_2)^n}{K + (pO_2)^n} where n is greater than 1 due to the cooperative binding of oxygen.

      Thus, the correct combination is:

      • Myoglobin: curve A, reaction i, equations III and IV.

      • Hemoglobin: curve B, reaction ii, equations I and II.

      Information Booster:  
      • Curve A (Myoglobin): Myoglobin is a monomeric protein that binds oxygen non-cooperatively, which results in a hyperbolic curve. This indicates that as oxygen binds, the affinity remains constant throughout the binding process. The Hill coefficient (n = 1) reflects this non-cooperative binding.

      • Curve B (Hemoglobin): Hemoglobin is a tetrameric protein that exhibits cooperative binding, which leads to a sigmoidal curve. The binding of the first oxygen molecule increases the affinity for the next molecules of oxygen, resulting in a steep rise in oxygen binding as the partial pressure of oxygen increases. The Hill coefficient (n > 1) reflects this positive cooperativity.

      • Reaction i and ii:

        • Reaction i: Describes the binding of a single molecule of oxygen to myoglobin, with a simple reversible reaction where oxygen binds to the myoglobin protein in a non-cooperative manner.

        • Reaction ii: Describes the cooperative binding of oxygen to hemoglobin, where binding of oxygen increases the affinity of hemoglobin for additional oxygen molecules.

        • Additional Information:  
        • Equations III and IV:

          • Equation III: This is used to describe myoglobin's binding of oxygen, which follows a simple hyperbolic model.

          • Equation IV: This could also describe the binding of oxygen in a non-cooperative manner, fitting with myoglobin’s behavior.

        • Equations I and II:

          • Equation I: Describes the cooperative binding of oxygen to hemoglobin, represented by a sigmoidal curve.

          • Equation II: Another way of describing the cooperative oxygen binding in hemoglobin, which takes into account the cooperative nature of oxygen binding to hemoglobin.

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