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The pH of water in Lonar lake was found to be 10.5, 10.3, 10.1, 10.4, 10.7, and 10.4 for measurements taken once daily over six days. What would be th
Question

The pH of water in Lonar lake was found to be 10.5, 10.3, 10.1, 10.4, 10.7, and 10.4 for measurements taken once daily over six days. What would be the average pH of the lake water during this period?

A.

10.56

B.

10.26

C.

10.36

D.

10.46

Correct option is C

To calculate the average pH of the lake water over the six days, we take the sum of all pH values and divide it by the number of days.

Given pH values over six days:
10.5, 10.3, 10.1, 10.4, 10.7, and 10.4

Step 1: Sum of all values:
10.5 + 10.3 + 10.1 + 10.4 + 10.7 + 10.4 = 62.4

Step 2: Divide the sum by the number of observations (6):
62.4 ÷ 6 = 10.4

10.4 is close to 10.36 so option C is correct answer.

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