The number 56890065 is completely divisible by only:

Correct option is B

Given:

Number = 56890065

Concept Used:

Divisibility by 3: A number is divisible if the sum of digits is divisible by 3.

Divisibility by 9: A number is divisible if the sum of digits is divisible by 9.

Divisibility by 4: A number is divisible if its last two digits are divisible by 4.

Divisibility by 11: Difference between the sum of digits at odd and even places is divisible by 11.

Divisibility by 6: Number must be divisible by both 2 and 3.

Solution:

Sum of digits​
5 + 6 + 8 + 9 + 0 + 0 + 6 + 5 = 39

​For 3: 39 ÷ 3 = 13 → divisible

For 9: 39 ÷ 9 = 4 remainder 3 → not divisible

​Last two digits = 65 → not divisible by 4

​Check divisibility by 11

Odd place digits = 5 + 8 + 0 + 6 = 19
Even place digits = 6 + 9 + 0 + 5 = 20
Difference = |19 – 20| = 1 → not divisible by 11

​Check divisibility by 6

​Needs divisibility by 2 and 3.

Number ends with 5 → not divisible by 2 → so not divisible by 6

​Check divisibility by 7

56890065 ÷ 7 =  not divisible

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