The nominal marks obtained by students who appeared in a test are given below. Find the median marks of the students.

Marks	11	20	8	16	29	22
No. of students	14	5	11	9	3	8

Correct option is C

Given:

The nominal marks obtained by students who appeared in a test

Formula Used:

Median if n is odd = $$\frac{n+1}{2}^{th}$$​ value

If n is even  = $$\frac{\left(\frac{n}{2}\right)^{th} value + \left(\frac{n}{2}+1\right)^{th} value}{2}$$​​

Solution:

Arranging the data in ascending order and adding the cumulative frequency

Here n = 50 is an even number

Hence, Median = $$\frac{\left(\frac{n}{2}\right)^{th} value + \left(\frac{n}{2}+1\right)^{th} value}{2}$$​​

​$$= \frac{\left(\frac{50}{2}\right)^{th} value + \left(\frac{50}{2}+1\right)^{th} value}{2}$$​​

​$$= \frac{(25)^{th} value + 26^{th} value}{2}$$​​

​$$= \frac{11+16}{2} = 13.5$$​​