The median of the observations 87, 56, 27, 31, 13, 39, 18, 80, 98, 92 and 25 is:
Given:
The set of observations is: 87, 56, 27, 31, 13, 39, 18, 80, 98, 92, 25
Formula Used:
Median (for odd number of terms) = Value at the position , where n is the number of observations arranged in ascending order.
Solution:
Arrange the data in ascending order: 13, 18, 25, 27, 31, 39, 56, 80, 87, 92, 98
Total number of terms (n) = 11 (which is odd)
Position of the median = = 6th position
6th value in the sorted list = 39
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The following is the distribution of ages (in years) of children in a group:
What is the median age (in years) of children ?
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The median of the observations 6, 48, 32, 3, 37 and 18 is:
In the following frequency distribution
| Height (in cm) | 140–145 | 145–150 | 150–155 | 155–160 | 160–165 | 165–170 |
| No. of students | 13 | 15 | 9 | 10 | 8 | 5 |
The sum of the upper limit of the modal class and the lower limit of the median class:
