The maximum length of a rod (in m) that can be kept in a cuboidal room of length 10 m, breadth 6 m and height 8 m, is:

Correct option is C

Given:
Length of room = 10 m
Breadth of room = 6 m
Height of room = 8 m
Formula Used:
Longest rod in cuboid = √(l² + b² + h²)
Solution:
​$$\text{Longest rod in cuboid} = \sqrt{10^2 + 6^2 + 8^2} \\= \sqrt{100 + 36 + 64} \\= \sqrt{200} \\= 10\sqrt{2}$$​​