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    The marked price of an article is ₹2,800. It is sold at three successive discounts of 15%, 8% and 5%. Find the selling price of the article (in ₹).
    Question

    The marked price of an article is ₹2,800. It is sold at three successive discounts of 15%, 8% and 5%. Find the selling price of the article (in ₹).

    A.

    2,080.12

    B.

    1,890.20

    C.

    1,997.26

    D.

    1,923.56

    Correct option is A

    Given:
    Marked price (MP) = ₹2,800
    Successive discounts: 15%, 8%, and 5%
    Formula Used:
    Selling price after successive discounts:
    Selling Price = MP×(1First Discount100)×(1Second Discount100)×(1Third Discount100)\text{MP} \times \left( 1 - \frac{\text{First Discount}}{100} \right) \times \left( 1 - \frac{\text{Second Discount}}{100} \right) \times \left( 1 - \frac{\text{Third Discount}}{100} \right)​​
    Solution:
    Apply the first discount of 15%:
    After 1st discount = 2800×(115100)=2800×0.85=2380 2800 \times \left( 1 - \frac{15}{100} \right) = 2800 \times 0.85 = 2380​​
    Apply the second discount of 8%:
    After 2nd discount = 2380×(18100)=2380×0.92=2189.602380 \times \left( 1 - \frac{8}{100} \right) = 2380 \times 0.92 = 2189.60​​
    Apply the third discount of 5%:
    After 3rd discount = 2189.60×(15100)=2189.60×0.95=2,080.122189.60 \times \left( 1 - \frac{5}{100} \right) = 2189.60 \times 0.95 = 2,080.12​​
    Thus, the  correct option is (a) ₹2,080.12

    Alternate Solution:

    Let, Selling price = x

    15% = 320-\frac{3}{20} ; 8% = 225-\frac{2}{25} ; 5% =120-\frac{1}{20}​​

    x = 2800×1720×2325×1920 2800 \times \frac{17}{20} \times \frac{23}{25}\times \frac{19}{20} = ₹2,080.12

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