The marked price of a crockery was Rs 15400/- and was offering a discount of 12%. Harsh bargained with the shopkeeper to get a successive discount and brought the crockery for Rs 10164/- What was the second discount offered by the shopkeeper?

Correct option is B

Given:
Marked Price (MP) = Rs 15400
First Discount = 12%
Final Price after successive discounts = Rs 10164
Formula Used:
Selling Price after first discount = $$\text{MP} \times \left(1 - \frac{\text{First Discount}}{100}\right)$$​​
Selling Price after second discount = $$\text{Price after first discount} \times \left(1 - \frac{\text{Second Discount}}{100}\right)$$​​
Solution:
​$$\text{Price after first discount} = 15400 \times (1 - \frac{12}{100})\\\text{Price after first discount} = 15400 \times 0.88 = 13552$$​​
 Let the second discount be D%. 
​$$10164 = 13552 \times (1 - \frac{D}{100})\\ (1 - \frac{D}{100}) = \frac{10164}{13552}$$​​
​$$1 - \frac{D}{100} = \frac{10164 }{13552}\\\ \\D = (1 - \frac{10164 }{13552}) \times 100\\\ \\D = (1 - 0.75) \times 100 = 25\%$$​​
Thus, the second discount offered by the shopkeeper was 25%.