The length of the base of a parallelogram is (4x² – 7xy + y²) m and its height is (x + y) m. Find the area of parallelogram, when x = 3 and y = –2.

Correct option is B

Given:

Length of the base of the parallelogram: $$4x^2 - 7xy + y^2$$​ meters

Height of the parallelogram: x + y meters

Values for x = 3 and y = -2

Formula Used:

Area of a parallelogram = Base × Height

Solution:  

Area of parallelogram = $$(4x^2 - 7xy + y^2) \times (x + y)$$​​

Substitute x = 3 and y = -2 into the expressions for the base and height 

Area of parallelogram = $$(4(3)^2 - 7(3)(-2) + (-2)^2)\times(3 + (-2))$$​​

​$$= (4(9) + 7(6) + 4)\times(1)$$​​

​$$=(36 + 42 + 4)\times(1)$$​​

​$$= 82 \times 1$$​​

​$$= 82\ m^2$$​​