arrow
arrow
arrow
The height of a tower is h meters. It is found that, when walking 100 m towards it in a horizontal line through its base, the elevation of its top cha
Question

The height of a tower is h meters. It is found that, when walking 100 m towards it in a horizontal line through its base, the elevation of its top changes from 30° to 60°, h is equal to:

A.

100 m

B.

100√3 m

C.

50 m

D.

50√3 m

Correct option is D

Given:

Initial angle = 30°
Final angle = 60°
Distance walked = 100 m

Formula:
tan(θ) = height / base

Solution:
Let final distance from tower = x
Then from triangle with 60°:
tan(60°) = h / x → √3 = h / x → h = x√3

From triangle with 30°:
tan(30°) = h / (x + 100) → 1/√3 = h / (x + 100)

Substitute h from above:
1/√3 = (x√3) / (x + 100)
Cross-multiplying:
x + 100 = 3x → 2x = 100 → x = 50
Then h = x√3 = 50√3

Final Answer: (d) 50√3 m

Free Tests

Free
Must Attempt

OSSC CGL 2024 Prelims PYP (Held on 20-Oct-2024)

languageIcon English
  • pdpQsnIcon150 Questions
  • pdpsheetsIcon150 Marks
  • timerIcon150 Mins
languageIcon English
Free
Must Attempt

Odisha GK Test 01

languageIcon English
  • pdpQsnIcon10 Questions
  • pdpsheetsIcon10 Marks
  • timerIcon10 Mins
languageIcon English
Free
Must Attempt

OSSC CGL Prelims Full Mock Test 01

languageIcon English
  • pdpQsnIcon150 Questions
  • pdpsheetsIcon150 Marks
  • timerIcon150 Mins
languageIcon English

Similar Questions

test-prime-package

Access ‘Odisha B.Ed’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
383k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow