The given graph shows the percentage-wise distribution of different mobile phone models (A to F) produced by a mobile company in 2008 and 2009. The total number of mobile phones produced in 2008 was 4,50,000 and that in 2009 was 6,40,000.

(If a value for any model in between a range, consider it to be at midpoint, e.g any point between 10 and 20 should be considered 15.)

If 90% of Model C sets produced by the company were sold each year, then how many of them were remaining at the end of 2009?

Correct option is B

Given:

Total number of mobile phones produced in 2008 = 4,50,000

Total number of mobile phones produced in 2009 = 6,40,000

Solution:

From the graph:

In 2008, the percentage of Model C phones produced = 20%.

In 2009, the percentage of Model C phones produced = 15%.

For 2008:

Number of Model C phones produced in 2008 = 20% of 4,50,000

​$$= \frac{20}{100} \times 4,50,000 = 90,000 \text{ phones}$$​​

For 2009:

Number of Model C phones produced in 2009 = 15% of 6,40,000

​$$= \frac{15}{100} \times 6,40,000 = 96,000 \text{ phones}$$​​

90% of the Model C phones produced each year were sold.

For 2008:

Number of Model C phones sold in 2008 = 90% of 90,000

​$$= \frac{90}{100} \times 90,000 = 81,000 \text{ phones}$$​​

For 2009:

Number of Model C phones sold in 2009 = 90% of 64,000

​$$= \frac{90}{100} \times 96,000 = 86,400 \text{ phones}$$​​

Phones that were not sold in 2008 remain as inventory into 2009.

Remaining Model C phones from 2008:

Phones remaining from 2008 = Total produced in 2008 - Phones sold in 2008

=90,000−81,000 = 9,000 phones

Remaining Model C phones from 2009:

Phones remaining from 2009 = Total produced in 2009 - Phones sold in 2009

= 96,000 - 86,400 = 9,600 phones

Total remaining Model C phones at the end of 2009.

Total remaining Model C phones = 9,600 + 9,000 = 18,600 phones