The generation of hydroelectric power does not depend on:

Correct option is D

​$$\text{The amount of electrical energy that can be generated by a hydroelectric power plant is given as:} \\E = K \cdot \gamma \cdot Q \cdot H \cdot \eta \quad \{ K \text{ is constant} \} \\[10pt]\text{From the above expression, it is clear that:} \\[10pt]1. \text{Specific weight of water } (\gamma) : \text{The electrical power generated is proportional to } \gamma \\\text{when } Q, H, \text{ and } \eta \text{ are constant.} \\E \propto \gamma \\[10pt]2. \text{Available water head } (H) : \text{The electrical power is proportional to } H \\\text{when } Q, \gamma, \text{ and } \eta \text{ are constant.} \\E \propto H \\[10pt]3. \text{Generation efficiency } (\eta) : \text{The electrical power is proportional to } \eta \\\text{when } Q, \gamma, \text{ and } H \text{ are constant.} \\E \propto \eta \\[10pt]4. \text{Flow rate of water } (Q) : \text{The electrical power is proportional to } Q \\\text{when } \gamma, H, \text{ and } \eta \text{ are constant.} \\E \propto Q \\[10pt]\text{However, the efficiency of the evaporator does not influence hydroelectric power} \\\text{generation as it is unrelated to this process.}$$​​