The frequency of an electromagnetic (EM) wave is 6 × $$10^{14}$$​ Hz. The wavelength of the EM wave is _________, and it falls in the range ___________.

Correct option is A

​$$\text{Given:} \\\text{Frequency of the EM wave, } f = 6 \times 10^{14} \, \text{Hz} \\\text{Speed of light, } c = 3 \times 10^8 \, \text{m/s} \\\lambda = \frac{c}{f} \\\lambda = \frac{3 \times 10^8}{6 \times 10^{14}} = 0.5 \times 10^{-6} \, \text{m} = 500 \, \text{nm}$$

A wavelength of 500 nm falls within the visible light range (approximately 400–700 nm).​​