The electric field of a plane electromagnetic wave oscillates sinusoidally with a frequency of 2.0 × $$10^{10}$$​ Hz and an amplitude of 60 $$\text{Vm}^{-1}$$​. The wavelength (in cm) of the wave is (c = 3 × $$10^8\space\text{ms}^{-1}$$​):

Correct option is A

​$$\text{To calculate the wavelength of the electromagnetic wave, we use the formula:} \\c = \lambda \cdot f \\\text{Where:} \\c = \text{speed of light in a vacuum} \, (3 \times 10^8 \, \text{m/s}), \\\lambda = \text{wavelength of the wave}, \\f = \text{frequency of the wave}. \\\text{Given:} \\c = 3 \times 10^8 \, \text{m/s}, \\f = 2.0 \times 10^{10} \, \text{Hz}. \\\text{We can rearrange the formula to solve for wavelength:} \\\lambda = \frac{c}{f} \\\text{Substitute the given values:} \\\lambda = \frac{3 \times 10^8}{2.0 \times 10^{10}} = 0.015 \, \text{m} = 1.5 \, \text{cm}$$​​