Given:
Total number of students in the university = 15,000
Percentage of fee waiver seats:
M.Tech = 15%
M.Com = 30%
MBA = 16%
MCA= 18%
M.sc= 21%
Solution:
M.Tech fee waiver seats:
15% of 15,000 = 15000 = 2250
M.Com fee waiver seats:
30% of 15000 = × 15000 = 4500
Total number of fee waiver seats in M.Tech and M.Com together 2,250+4,500=6,750
The total number of fee waiver seats in M.Tech and M.Com together is 6,750
Thus,correct option is (b)
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