Pie-chart I shows the distribution of students who appeared in Board examination from schools A, B, C, D and E and pie-chart II shows the

distribution of students who passed the examination from these schools. Read both these pie-charts and answer the question :

​The total number of students who failed from schools B and D is what percent of the total number of students who passed from schools A and C?

Correct option is B

​​​$$\textbf{Given:} \\\text{Total students appeared} = 1800 \\\text{Total students passed} = 1500 \\\textbf{Concept Used:} \\\text{Percentage calculation} \\\textbf{Formula Used:} \\\text{Number} = \frac{\text{Percentage}}{100} \times \text{Total} \\\textbf{Solution:} \\B_{\text{appeared}} = \frac{18}{100} \times 1800 = 324 \\B_{\text{passed}} = \frac{18}{100} \times 1500 = 270 \\B_{\text{failed}} = 324 - 270 = 54 \\D_{\text{appeared}} = \frac{21}{100} \times 1800 = 378 \\D_{\text{passed}} = \frac{24}{100} \times 1500 = 360 \\D_{\text{failed}} = 378 - 360 = 18 \\\text{Total failed (B + D)} = 54 + 18 = 72 \\A_{\text{passed}} = \frac{15}{100} \times 1500 = 225 \\C_{\text{passed}} = \frac{21}{100} \times 1500 = 315 \\\text{Total passed (A + C)} = 225 + 315 = 540 \\\text{Required percentage} = \frac{72}{540} \times 100 = 13.33\% \\\textbf{Final Answer:} \\13.33\%$$​​