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The focal length of a diverging lens os 50 cm. The power of the lens is:
Question

The focal length of a diverging lens os 50 cm. The power of the lens is:

A.

2 D

B.

–2D

C.

–5D

D.

5D

Correct option is B

The Correct Answer is (B) –2D

Explanation:

The power (PPP) of a lens is calculated using the formula:

P=100fP= \frac{100}{f}​​

where:

  • P = power of the lens (in diopters, D),
  • f = focal length of the lens (in cm).

Step 1: Identify the focal length

  • Given focal length (f) = 50 cm.
  • Since it is a diverging lens, the focal length is negative: f=−50 cm.

Step 2: Substitute into the formula

P=100f=10050=2DP=\frac{100}{f} = \frac{100}{-50} = −2D​​

Key Facts:

·         The focal length of a diverging lens is always negative.

·         A negative power indicates a diverging lens.

·         Power is measured in diopters (D), where 1D=1 m−1.

·         Shorter focal lengths correspond to higher powers.

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