Correct option is C
Key points based on the provided feedback regulation:
AHAS enzyme is synergistically inhibited by Leucine and Valine. So, the ahas2-1p mutant, which is feedback resistant, will likely grow in conditions where Leu or Val + Leu are present but may be limited in other conditions.
IPMS enzyme is only inhibited by Leucine. Therefore, the ipms1-1p mutant, which is feedback resistant, will grow in conditions that contain Leu, but it might not grow in conditions where Leu is absent or insufficient.
Evaluating the options:
Option 1: ahas2-1p will grow in (C) only, and ipms1-1p will grow in (B) only.
- This is incorrect because ahas2-1p will also grow in (A) and ipms1-1p will grow in both (A) and (B).
Option 2: ahas2-1p will grow only in (D) and ipms1-1p will grow in both (A) and (B).
- This is incorrect because ahas2-1p will grow in more conditions than just (D), and ipms1-1p will grow in more than just (A) and (B).
Option 3: ahas2-1p will grow in both (A) and (C) and ipms1-1p will grow in both (A) and (B).
- This is correct. ahas2-1p (the mutant for AHAS) will grow in MS medium only (A) and MS medium supplemented with Val + Leu (C) because it is resistant to Leu and Val feedback inhibition. ipms1-1p (the mutant for IPMS) will grow in MS medium only (A) and MS medium supplemented with Leu only (B), as it is resistant to Leu inhibition.
Option 4: Both ahas2-1p and ipms1-1p mutants will grow in (A) only.
- This is incorrect because both mutants will grow in additional combinations as explained above.

