Correct option is A
Sol. Step 1: Calculate the time difference between the two jeeps The second jeep starts 10 minutes later than the first jeep. 10 minutes = 10/60 = 1/6 hours
Step 2: Calculate the distance covered by the first jeep in 1/6 hours Distance = Speed × Time = 20 × (1/6) = 3.33 km
So, the remaining distance between the two jeeps = 120 - 3.33 = 116.67 km
Step 3: Calculate the combined speed of both jeeps moving towards each other Combined speed = 20 km/h + 30 km/h = 50 km/h
Step 4: Calculate the time it will take for both jeeps to meet Time = Distance ÷ Speed = 116.67 ÷ 50 = 2.333 hours (which is 2 hours 20 minutes)
Step 5: Calculate the distance travelled by the first jeep in 2.333 hours Distance = Speed × Time = 20 × 2.333 = 46.66 km
Step 6: Calculate the distance travelled by the second jeep in 2.333 hours Distance = Speed × Time = 30 × 2.333 = 69.99 km
Step 7: The meeting point:
· The first jeep travels 46.66 km from T1.
· The second jeep travels 69.99 km from T2.
· The total distance is 120 km, so the two jeeps will meet at:
· 51.78 km from T1
· 98.22 km from T2