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The distance between two temples, T1 and T2, is 120 km. · One jeep travels from T1 to T2 at an average speed of 20 km/h. · Another jeep starts 1
Question

The distance between two temples, T1 and T2, is 120 km.
· One jeep travels from T1 to T2 at an average speed of 20 km/h.
· Another jeep starts 10 minutes later and travels from T2 to T1 at an average speed of 30 km/h. Question: At what distance from T1 and T2 will the two jeeps meet?

A.

51.78 km and 98.22 km

B.

54.60 km and 95.47 km

C.

41.81 km and 78.19 km

D.

45.16 km and 74.84 km

Correct option is A


Sol. Step 1: Calculate the time difference between the two jeeps The second jeep starts 10 minutes later than the first jeep. 10 minutes = 10/60 = 1/6 hours
Step 2: Calculate the distance covered by the first jeep in 1/6 hours Distance = Speed × Time = 20 × (1/6) = 3.33 km
So, the remaining distance between the two jeeps = 120 - 3.33 = 116.67 km
Step 3: Calculate the combined speed of both jeeps moving towards each other Combined speed = 20 km/h + 30 km/h = 50 km/h
Step 4: Calculate the time it will take for both jeeps to meet Time = Distance ÷ Speed = 116.67 ÷ 50 = 2.333 hours (which is 2 hours 20 minutes)
Step 5: Calculate the distance travelled by the first jeep in 2.333 hours Distance = Speed × Time = 20 × 2.333 = 46.66 km
Step 6: Calculate the distance travelled by the second jeep in 2.333 hours Distance = Speed × Time = 30 × 2.333 = 69.99 km
Step 7: The meeting point:
· The first jeep travels 46.66 km from T1.
· The second jeep travels 69.99 km from T2.
· The total distance is 120 km, so the two jeeps will meet at:
· 51.78 km from T1
· 98.22 km from T2

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