The digit of hundred's place value of 19! is:

Correct option is D

Given:

Find the hundreds digit of ( 19! )

Solution:

19! = 19$$\times 18 \times 17 \times \ldots \times 1$$​​

( 19!) is divisible by ( 1000) (since ( 10!) already has more than three factors of 2 and 5).

Therefore, $$( 19! \mod 1000 = 0 )$$​​

( 000).

Thus, the hundreds digit is ( 0) 

Alternate Method: 

19! 

If the last digit is 5, it becomes 0 when multiplied by 2 

15, 5 ,10 

So that 000