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    The cost of a motorbike is 75% less than the cost of a car. The cost of a car decreases by 25% and that of a motorbike increases by 40%.Statement I:&n
    Question

    The cost of a motorbike is 75% less than the cost of a car. The cost of a car decreases by 25% and that of a motorbike increases by 40%.

    Statement I:  The new cost of motorbike is 5313\frac{1}{3}​​% less than new cost of car?​

    Statement II: The total new cost of one car and two motorbikes is 313\frac{1}{3}​% more than their total initial cost. ​

    Which of the above statements is/are correct?

    A.

    Neither I nor II

    B.

    II only

    C.

    I only

    D.

    Both I and II

    Correct option is C

    Given:

    • Initial cost of motorbike is 75% less than that of a car.
      That means:
      If car = ₹100, then motorbike = ₹25
    • Car decreases by 25% → New cost of car = ₹100 − ₹25 = ₹75
    • Motorbike increases by 40% → New cost = ₹25 + 40% of ₹25 = ₹25 + ₹10 = ₹35

    Statement I:

    Is the new cost of motorbike 5313\frac{1}{3}​% less than new cost of car?

    New cost of car = ₹75
    New cost of bike = ₹35

    Let’s find the % decrease of bike w.r.t car:

    Percentage less=753575×100=4075×100=53.3%\text{Percentage less} = \frac{75 - 35}{75} \times 100 = \frac{40}{75} \times 100 = 53.\overline{3}\%

    So, Statement I is correct

    Statement II:

    Compare total new cost vs total old cost for 1 car + 2 bikes

    Initial total cost:

    • 1 car = ₹100
    • 2 motorbikes = ₹25 × 2 = ₹50
      → Total initial = ₹150

    New total cost:

    • 1 car = ₹75
    • 2 motorbikes = ₹35 × 2 = ₹70
      → Total new = ₹145

    Now find % change: 

    Change=145150150×100=5150×100=3.3%\text{Change} = \frac{145 - 150}{150} \times 100 = \frac{-5}{150} \times 100 = -3.\overline{3}\%

    So it is not 313\frac{1}{3}​% more, it is actually 3.33% less

    Statement II is incorrect

    Final Answer: (C) I only​​


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