A bus is moving at a speed of 82 km/hr. If its speed is reduced by 28%, then what will be the new speed of the bus (in km/hr)?

Correct option is A

Given:
Initial Speed = 82 km/hr
Reduction Percentage = 28%
Solution:
Determine the percentage of the new speed.
​$$\text{New Speed \%} = 100\% - 28\% = 72\%$$​​
Calculate 72% of the initial speed.
​$$\text{New Speed} = 82 \times \frac{72}{100} \\= 82 \times 0.72$$​​
59.04 km/hr
So the correct answer is (a)