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The concentration of three acids, P, Q and R, is given as 15%, 25% and 35%, respectively. They are mixed in the ratio of x : 3 : 5, resulting in a 28%
Question

The concentration of three acids, P, Q and R, is given as 15%, 25% and 35%, respectively. They are mixed in the ratio of x : 3 : 5, resulting in a 28% concentration solution. What is the value of x?

A.

2

B.

4

C.

1

D.

3

Correct option is A

Given:

Concentration of three acids are 15%, 25% and 35%

Resulting concentration =28%

Acids mixed in the ratio = x : 3 : 5

Formula Used:

Ratio concepts used

Solution:

Assume that acids a, b and c are mixed in the ratio 10kx ,30k and 50k

Total mixture =10kx+30k+50k=10k(x+3+5)=10k(x+8) 10kx +30k+50k = 10k(x+3+5) = 10k(x+8)​​

Acids are:

a=15100×10kx=1.5kxa= \frac{15}{100}\times 10kx = 1.5kx​​

b=25100×30k=7.5kb= \frac{25}{100} \times 30k = 7.5k​​

c=35100×50k=17.5kc= \frac{35}{100} \times 50k = 17.5k​​

Total acid =1.5kx+7.5k+17.5k=k(1.5x+25) 1.5kx +7.5k +17.5k = k(1.5x+25)​​

Resultant is 28% mixture:

k(1.5x+25)10k(x+8)=28100\frac{k(1.5x+25)}{10k(x+8)} =\frac{28}{100}​​

100(1.5x+25)=280(x+8)100 (1.5x+25) = 280(x+8)​​

150x+2500=280x+2240150x+2500 = 280x + 2240​​

25002240=280x150x2500-2240 = 280x- 150x

260=130x260 = 130x​​

x=2x= 2​​

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