The average score of a cricketer in 20 matches is 40 runs. If his highest score in a match was 78 runs, what is the average of his scores in the remaining 19 matches?

Correct option is D

Given:

The average score of the cricketer in 20 matches = 40 runs

The highest score in a match = 78 runs

Formula Used:

Average = $$\text{Average} \times \text{Number of matches}$$​​

Total score in remaining 19 matches = Total score in 20 matches − Highest score

Average score in remaining 19 matches = $$\frac{\text{Total score in remaining 19 matches}}{19}$$​​

Solution:

Total score in 20 matches:

Total score in 20 matches = 40 × 20 = 800

Total score in the remaining 19 matches:

Total score in remaining 19 matches = 800 – 78 = 722

Average score in remaining 19 matches:

Average score in remaining 19 matches = $$\frac{722}{19}$$​ = 38

Thus, The average score of the cricketer in the remaining 19 matches is 38 runs.