The average of three consecutive odd numbers is 43 . What is the average of smallest and largest of these numbers ?

Correct option is C

Given:
Average of three consecutive odd numbers = 43
Formula Used:
For numbers forming an Arithmetic Progression (AP), the average of all numbers equals the average of the first and the last numbers.
Solution:
Let the three consecutive odd numbers be x, x + 2, and x + 4.
Average = $$\frac{x + x + 2 + x + 4}{3} = 43$$​​
​$$\frac{3x + 6}{3} = 43$$​​
x + 2 = 43
x = 41
The three numbers are 41, 43, and 45.
The smallest number is 41 and the largest number is 45.
Average of the smallest and largest = $$\frac{41 + 45}{2} = \frac{86}{2}$$​ = 43
Final Answer
So the correct answer is (c)